3(2x-3)(x=1)=4

Solution for 3(2x-3)(x=1)=4 equation:

3(2x-3)(x=1)=4

We move all terms to the left:

3(2x-3)(x-(1))=0

We multiply parentheses ..

3(+2x^2-2x-3x+3)=0

We multiply parentheses

6x^2-6x-9x+9=0

We add all the numbers together, and all the variables

6x^2-15x+9=0

a = 6; b = -15; c = +9;
Δ = b2-4ac
Δ = -152-4·6·9
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-3}{2*6}=\frac{12}{12}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+3}{2*6}=\frac{18}{12}
=1+1/2
$