3(2x-20)=2(x+8)

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Solution for 3(2x-20)=2(x+8) equation: 



3(2x-20)=2(x+8)

We move all terms to the left:

3(2x-20)-(2(x+8))=0

We multiply parentheses

6x-(2(x+8))-60=0



We calculate terms in parentheses: -(2(x+8)), so:

2(x+8)

We multiply parentheses

2x+16

Back to the equation:

-(2x+16)



We get rid of parentheses

6x-2x-16-60=0

We add all the numbers together, and all the variables

4x-76=0

We move all terms containing x to the left, all other terms to the right

4x=76

x=76/4

x=19

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