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3(2x-2)=2(x+4)+10
We move all terms to the left:
3(2x-2)-(2(x+4)+10)=0
We multiply parentheses
6x-(2(x+4)+10)-6=0
We calculate terms in parentheses: -(2(x+4)+10), so:We get rid of parentheses
2(x+4)+10
We multiply parentheses
2x+8+10
We add all the numbers together, and all the variables
2x+18
Back to the equation:
-(2x+18)
6x-2x-18-6=0
We add all the numbers together, and all the variables
4x-24=0
We move all terms containing x to the left, all other terms to the right
4x=24
x=24/4
x=6
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