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3(2x-2)=2(9x+1)
We move all terms to the left:
3(2x-2)-(2(9x+1))=0
We multiply parentheses
6x-(2(9x+1))-6=0
We calculate terms in parentheses: -(2(9x+1)), so:We get rid of parentheses
2(9x+1)
We multiply parentheses
18x+2
Back to the equation:
-(18x+2)
6x-18x-2-6=0
We add all the numbers together, and all the variables
-12x-8=0
We move all terms containing x to the left, all other terms to the right
-12x=8
x=8/-12
x=-2/3
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