3(2x-2)=2(3x-3)*

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Solution for 3(2x-2)=2(3x-3)* equation: 



3(2x-2)=2(3x-3)*

We move all terms to the left:

3(2x-2)-(2(3x-3)*)=0

We multiply parentheses

6x-(2(3x-3)*)-6=0



We calculate terms in parentheses: -(2(3x-3)*), so:

2(3x-3)*

We multiply parentheses

6x-6

Back to the equation:

-(6x-6)



We get rid of parentheses

6x-6x+6-6=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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