3(2x-2)-2=3(x-5)+28

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Solution for 3(2x-2)-2=3(x-5)+28 equation: 



3(2x-2)-2=3(x-5)+28

We move all terms to the left:

3(2x-2)-2-(3(x-5)+28)=0

We multiply parentheses

6x-(3(x-5)+28)-6-2=0



We calculate terms in parentheses: -(3(x-5)+28), so:

3(x-5)+28

We multiply parentheses

3x-15+28

We add all the numbers together, and all the variables

3x+13

Back to the equation:

-(3x+13)



We add all the numbers together, and all the variables

6x-(3x+13)-8=0

We get rid of parentheses

6x-3x-13-8=0

We add all the numbers together, and all the variables

3x-21=0

We move all terms containing x to the left, all other terms to the right

3x=21

x=21/3

x=7

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