3(2x-10)=-4x+28

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Solution for 3(2x-10)=-4x+28 equation: 



3(2x-10)=-4x+28

We move all terms to the left:

3(2x-10)-(-4x+28)=0

We multiply parentheses

6x-(-4x+28)-30=0

We get rid of parentheses

6x+4x-28-30=0

We add all the numbers together, and all the variables

10x-58=0

We move all terms containing x to the left, all other terms to the right

10x=58

x=58/10

x=5+4/5

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