3(2x-10)+20=6x-10

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Solution for 3(2x-10)+20=6x-10 equation: 



3(2x-10)+20=6x-10

We move all terms to the left:

3(2x-10)+20-(6x-10)=0

We multiply parentheses

6x-(6x-10)-30+20=0

We get rid of parentheses

6x-6x+10-30+20=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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