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3(2x-1)=6+5(x-3)
We move all terms to the left:
3(2x-1)-(6+5(x-3))=0
We multiply parentheses
6x-(6+5(x-3))-3=0
We calculate terms in parentheses: -(6+5(x-3)), so:We get rid of parentheses
6+5(x-3)
determiningTheFunctionDomain 5(x-3)+6
We multiply parentheses
5x-15+6
We add all the numbers together, and all the variables
5x-9
Back to the equation:
-(5x-9)
6x-5x+9-3=0
We add all the numbers together, and all the variables
x+6=0
We move all terms containing x to the left, all other terms to the right
x=-6
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