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3(2x-1)=5(x-5)
We move all terms to the left:
3(2x-1)-(5(x-5))=0
We multiply parentheses
6x-(5(x-5))-3=0
We calculate terms in parentheses: -(5(x-5)), so:We get rid of parentheses
5(x-5)
We multiply parentheses
5x-25
Back to the equation:
-(5x-25)
6x-5x+25-3=0
We add all the numbers together, and all the variables
x+22=0
We move all terms containing x to the left, all other terms to the right
x=-22
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