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3(2x-1)=5(x+2)+x
We move all terms to the left:
3(2x-1)-(5(x+2)+x)=0
We multiply parentheses
6x-(5(x+2)+x)-3=0
We calculate terms in parentheses: -(5(x+2)+x), so:We get rid of parentheses
5(x+2)+x
We add all the numbers together, and all the variables
x+5(x+2)
We multiply parentheses
x+5x+10
We add all the numbers together, and all the variables
6x+10
Back to the equation:
-(6x+10)
6x-6x-10-3=0
We add all the numbers together, and all the variables
-13!=0
There is no solution for this equation
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