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3(2x-1)=4(x+2)-3x
We move all terms to the left:
3(2x-1)-(4(x+2)-3x)=0
We multiply parentheses
6x-(4(x+2)-3x)-3=0
We calculate terms in parentheses: -(4(x+2)-3x), so:We get rid of parentheses
4(x+2)-3x
We add all the numbers together, and all the variables
-3x+4(x+2)
We multiply parentheses
-3x+4x+8
We add all the numbers together, and all the variables
x+8
Back to the equation:
-(x+8)
6x-x-8-3=0
We add all the numbers together, and all the variables
5x-11=0
We move all terms containing x to the left, all other terms to the right
5x=11
x=11/5
x=2+1/5
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