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3(2x-1)=2(x+1)-1
We move all terms to the left:
3(2x-1)-(2(x+1)-1)=0
We multiply parentheses
6x-(2(x+1)-1)-3=0
We calculate terms in parentheses: -(2(x+1)-1), so:We get rid of parentheses
2(x+1)-1
We multiply parentheses
2x+2-1
We add all the numbers together, and all the variables
2x+1
Back to the equation:
-(2x+1)
6x-2x-1-3=0
We add all the numbers together, and all the variables
4x-4=0
We move all terms containing x to the left, all other terms to the right
4x=4
x=4/4
x=1
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