3(2x-1)=(1/2)(4x-2)+2

Solution for 3(2x-1)=(1/2)(4x-2)+2 equation:

3(2x-1)=(1/2)(4x-2)+2

We move all terms to the left:

3(2x-1)-((1/2)(4x-2)+2)=0


Domain of the equation: 2)(4x-2)+2)!=0

x∈R


We add all the numbers together, and all the variables

3(2x-1)-((+1/2)(4x-2)+2)=0

We multiply parentheses

6x-((+1/2)(4x-2)+2)-3=0

We multiply parentheses ..

-((+4x^2+1/2*-2)+2)+6x-3=0

We multiply all the terms by the denominator


-((+4x^2+1+6x*2*-2)+2)-3*2*-2)+2)=0


We calculate terms in parentheses: -((+4x^2+1+6x*2*-2)+2), so:

(+4x^2+1+6x*2*-2)+2

We get rid of parentheses

4x^2+6x*2*+1-2+2

We add all the numbers together, and all the variables

4x^2+6x*2*+1

Wy multiply elements

4x^2+12x^2+1

We add all the numbers together, and all the variables

16x^2+1

Back to the equation:

-(16x^2+1)


We add all the numbers together, and all the variables

-(16x^2+1)=0

We get rid of parentheses

-16x^2-1=0

a = -16; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·(-16)·(-1)
Δ = -64
Delta is less than zero, so there is no solution for the equation