3(2x-1)-6=2(x+2)-5

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Solution for 3(2x-1)-6=2(x+2)-5 equation: 



3(2x-1)-6=2(x+2)-5

We move all terms to the left:

3(2x-1)-6-(2(x+2)-5)=0

We multiply parentheses

6x-(2(x+2)-5)-3-6=0



We calculate terms in parentheses: -(2(x+2)-5), so:

2(x+2)-5

We multiply parentheses

2x+4-5

We add all the numbers together, and all the variables

2x-1

Back to the equation:

-(2x-1)



We add all the numbers together, and all the variables

6x-(2x-1)-9=0

We get rid of parentheses

6x-2x+1-9=0

We add all the numbers together, and all the variables

4x-8=0

We move all terms containing x to the left, all other terms to the right

4x=8

x=8/4

x=2

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