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3(2x-1)-4(x+2)=2(x+5)
We move all terms to the left:
3(2x-1)-4(x+2)-(2(x+5))=0
We multiply parentheses
6x-4x-(2(x+5))-3-8=0
We calculate terms in parentheses: -(2(x+5)), so:We add all the numbers together, and all the variables
2(x+5)
We multiply parentheses
2x+10
Back to the equation:
-(2x+10)
2x-(2x+10)-11=0
We get rid of parentheses
2x-2x-10-11=0
We add all the numbers together, and all the variables
-21!=0
There is no solution for this equation
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