3(2x-1)-4(3x+2)=2(x-4)-(x+2)

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Solution for 3(2x-1)-4(3x+2)=2(x-4)-(x+2) equation: 



3(2x-1)-4(3x+2)=2(x-4)-(x+2)

We move all terms to the left:

3(2x-1)-4(3x+2)-(2(x-4)-(x+2))=0

We multiply parentheses

6x-12x-(2(x-4)-(x+2))-3-8=0



We calculate terms in parentheses: -(2(x-4)-(x+2)), so:

2(x-4)-(x+2)

We multiply parentheses

2x-(x+2)-8

We get rid of parentheses

2x-x-2-8

We add all the numbers together, and all the variables

x-10

Back to the equation:

-(x-10)



We add all the numbers together, and all the variables

-6x-(x-10)-11=0

We get rid of parentheses

-6x-x+10-11=0

We add all the numbers together, and all the variables

-7x-1=0

We move all terms containing x to the left, all other terms to the right

-7x=1

x=1/-7

x=-1/7

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