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3(2x-1)+5x=2(4x+2)+3+x
We move all terms to the left:
3(2x-1)+5x-(2(4x+2)+3+x)=0
We add all the numbers together, and all the variables
5x+3(2x-1)-(2(4x+2)+3+x)=0
We multiply parentheses
5x+6x-(2(4x+2)+3+x)-3=0
We calculate terms in parentheses: -(2(4x+2)+3+x), so:We add all the numbers together, and all the variables
2(4x+2)+3+x
determiningTheFunctionDomain 2(4x+2)+x+3
We add all the numbers together, and all the variables
x+2(4x+2)+3
We multiply parentheses
x+8x+4+3
We add all the numbers together, and all the variables
9x+7
Back to the equation:
-(9x+7)
11x-(9x+7)-3=0
We get rid of parentheses
11x-9x-7-3=0
We add all the numbers together, and all the variables
2x-10=0
We move all terms containing x to the left, all other terms to the right
2x=10
x=10/2
x=5
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