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3(2x-1)+4x=5(x+2)-13
We move all terms to the left:
3(2x-1)+4x-(5(x+2)-13)=0
We add all the numbers together, and all the variables
4x+3(2x-1)-(5(x+2)-13)=0
We multiply parentheses
4x+6x-(5(x+2)-13)-3=0
We calculate terms in parentheses: -(5(x+2)-13), so:We add all the numbers together, and all the variables
5(x+2)-13
We multiply parentheses
5x+10-13
We add all the numbers together, and all the variables
5x-3
Back to the equation:
-(5x-3)
10x-(5x-3)-3=0
We get rid of parentheses
10x-5x+3-3=0
We add all the numbers together, and all the variables
5x=0
x=0/5
x=0
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