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3(2x-1)+4=-2(3x-1)-1
We move all terms to the left:
3(2x-1)+4-(-2(3x-1)-1)=0
We multiply parentheses
6x-(-2(3x-1)-1)-3+4=0
We calculate terms in parentheses: -(-2(3x-1)-1), so:We add all the numbers together, and all the variables
-2(3x-1)-1
We multiply parentheses
-6x+2-1
We add all the numbers together, and all the variables
-6x+1
Back to the equation:
-(-6x+1)
6x-(-6x+1)+1=0
We get rid of parentheses
6x+6x-1+1=0
We add all the numbers together, and all the variables
12x=0
x=0/12
x=0
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