3(2x-1)+3=2(-8+x)

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Solution for 3(2x-1)+3=2(-8+x) equation: 



3(2x-1)+3=2(-8+x)

We move all terms to the left:

3(2x-1)+3-(2(-8+x))=0

We add all the numbers together, and all the variables

3(2x-1)-(2(x-8))+3=0

We multiply parentheses

6x-(2(x-8))-3+3=0



We calculate terms in parentheses: -(2(x-8)), so:

2(x-8)

We multiply parentheses

2x-16

Back to the equation:

-(2x-16)



We add all the numbers together, and all the variables

6x-(2x-16)=0

We get rid of parentheses

6x-2x+16=0

We add all the numbers together, and all the variables

4x+16=0

We move all terms containing x to the left, all other terms to the right

4x=-16

x=-16/4

x=-4

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