3(2x+6+2x+3x)=12

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Solution for 3(2x+6+2x+3x)=12 equation: 



3(2x+6+2x+3x)=12

We move all terms to the left:

3(2x+6+2x+3x)-(12)=0

We add all the numbers together, and all the variables

3(7x+6)-12=0

We multiply parentheses

21x+18-12=0

We add all the numbers together, and all the variables

21x+6=0

We move all terms containing x to the left, all other terms to the right

21x=-6

x=-6/21

x=-2/7

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