3(2x+5)=6x-2(1-x)+13

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Solution for 3(2x+5)=6x-2(1-x)+13 equation: 



3(2x+5)=6x-2(1-x)+13

We move all terms to the left:

3(2x+5)-(6x-2(1-x)+13)=0

We add all the numbers together, and all the variables

3(2x+5)-(6x-2(-1x+1)+13)=0

We multiply parentheses

6x-(6x-2(-1x+1)+13)+15=0



We calculate terms in parentheses: -(6x-2(-1x+1)+13), so:

6x-2(-1x+1)+13

We multiply parentheses

6x+2x-2+13

We add all the numbers together, and all the variables

8x+11

Back to the equation:

-(8x+11)



We get rid of parentheses

6x-8x-11+15=0

We add all the numbers together, and all the variables

-2x+4=0

We move all terms containing x to the left, all other terms to the right

-2x=-4

x=-4/-2

x=+2

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