3(2x+5)=4(x-3)-x

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Solution for 3(2x+5)=4(x-3)-x equation: 



3(2x+5)=4(x-3)-x

We move all terms to the left:

3(2x+5)-(4(x-3)-x)=0

We multiply parentheses

6x-(4(x-3)-x)+15=0



We calculate terms in parentheses: -(4(x-3)-x), so:

4(x-3)-x

We add all the numbers together, and all the variables

-1x+4(x-3)

We multiply parentheses

-1x+4x-12

We add all the numbers together, and all the variables

3x-12

Back to the equation:

-(3x-12)



We get rid of parentheses

6x-3x+12+15=0

We add all the numbers together, and all the variables

3x+27=0

We move all terms containing x to the left, all other terms to the right

3x=-27

x=-27/3

x=-9

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