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3(2x+5)=3(3x+3)
We move all terms to the left:
3(2x+5)-(3(3x+3))=0
We multiply parentheses
6x-(3(3x+3))+15=0
We calculate terms in parentheses: -(3(3x+3)), so:We get rid of parentheses
3(3x+3)
We multiply parentheses
9x+9
Back to the equation:
-(9x+9)
6x-9x-9+15=0
We add all the numbers together, and all the variables
-3x+6=0
We move all terms containing x to the left, all other terms to the right
-3x=-6
x=-6/-3
x=+2
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