3(2x+5)=-7(4x-5)+33x

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Solution for 3(2x+5)=-7(4x-5)+33x equation: 



3(2x+5)=-7(4x-5)+33x

We move all terms to the left:

3(2x+5)-(-7(4x-5)+33x)=0

We multiply parentheses

6x-(-7(4x-5)+33x)+15=0



We calculate terms in parentheses: -(-7(4x-5)+33x), so:

-7(4x-5)+33x

We add all the numbers together, and all the variables

33x-7(4x-5)

We multiply parentheses

33x-28x+35

We add all the numbers together, and all the variables

5x+35

Back to the equation:

-(5x+35)



We get rid of parentheses

6x-5x-35+15=0

We add all the numbers together, and all the variables

x-20=0

We move all terms containing x to the left, all other terms to the right

x=20

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