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3(2x+5)=(10x+4)-(4x-12)
We move all terms to the left:
3(2x+5)-((10x+4)-(4x-12))=0
We multiply parentheses
6x-((10x+4)-(4x-12))+15=0
We calculate terms in parentheses: -((10x+4)-(4x-12)), so:We get rid of parentheses
(10x+4)-(4x-12)
We get rid of parentheses
10x-4x+4+12
We add all the numbers together, and all the variables
6x+16
Back to the equation:
-(6x+16)
6x-6x-16+15=0
We add all the numbers together, and all the variables
-1!=0
There is no solution for this equation
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