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3(2x+5)-2x=(3x+6)
We move all terms to the left:
3(2x+5)-2x-((3x+6))=0
We add all the numbers together, and all the variables
-2x+3(2x+5)-((3x+6))=0
We multiply parentheses
-2x+6x-((3x+6))+15=0
We calculate terms in parentheses: -((3x+6)), so:We add all the numbers together, and all the variables
(3x+6)
We get rid of parentheses
3x+6
Back to the equation:
-(3x+6)
4x-(3x+6)+15=0
We get rid of parentheses
4x-3x-6+15=0
We add all the numbers together, and all the variables
x+9=0
We move all terms containing x to the left, all other terms to the right
x=-9
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