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3(2x+4)=2x+2(2x+6)
We move all terms to the left:
3(2x+4)-(2x+2(2x+6))=0
We multiply parentheses
6x-(2x+2(2x+6))+12=0
We calculate terms in parentheses: -(2x+2(2x+6)), so:We get rid of parentheses
2x+2(2x+6)
We multiply parentheses
2x+4x+12
We add all the numbers together, and all the variables
6x+12
Back to the equation:
-(6x+12)
6x-6x-12+12=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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