3(2x+4)=19-x

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Solution for 3(2x+4)=19-x equation: 



3(2x+4)=19-x

We move all terms to the left:

3(2x+4)-(19-x)=0

We add all the numbers together, and all the variables

3(2x+4)-(-1x+19)=0

We multiply parentheses

6x-(-1x+19)+12=0

We get rid of parentheses

6x+1x-19+12=0

We add all the numbers together, and all the variables

7x-7=0

We move all terms containing x to the left, all other terms to the right

7x=7

x=7/7

x=1

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