3(2x+4)+5(3x+2)=40

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Solution for 3(2x+4)+5(3x+2)=40 equation: 



3(2x+4)+5(3x+2)=40

We move all terms to the left:

3(2x+4)+5(3x+2)-(40)=0

We multiply parentheses

6x+15x+12+10-40=0

We add all the numbers together, and all the variables

21x-18=0

We move all terms containing x to the left, all other terms to the right

21x=18

x=18/21

x=6/7

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