3(2x+4)+13(2x+2)=39(x-8)

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Solution for 3(2x+4)+13(2x+2)=39(x-8) equation: 



3(2x+4)+13(2x+2)=39(x-8)

We move all terms to the left:

3(2x+4)+13(2x+2)-(39(x-8))=0

We multiply parentheses

6x+26x-(39(x-8))+12+26=0



We calculate terms in parentheses: -(39(x-8)), so:

39(x-8)

We multiply parentheses

39x-312

Back to the equation:

-(39x-312)



We add all the numbers together, and all the variables

32x-(39x-312)+38=0

We get rid of parentheses

32x-39x+312+38=0

We add all the numbers together, and all the variables

-7x+350=0

We move all terms containing x to the left, all other terms to the right

-7x=-350

x=-350/-7

x=+50

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