3(2x+4)+10+4X=40

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Solution for 3(2x+4)+10+4X=40 equation:


Simplifying
3(2x + 4) + 10 + 4X = 40

Reorder the terms:
3(4 + 2x) + 10 + 4X = 40
(4 * 3 + 2x * 3) + 10 + 4X = 40
(12 + 6x) + 10 + 4X = 40

Reorder the terms:
12 + 10 + 4X + 6x = 40

Combine like terms: 12 + 10 = 22
22 + 4X + 6x = 40

Solving
22 + 4X + 6x = 40

Solving for variable 'X'.

Move all terms containing X to the left, all other terms to the right.

Add '-22' to each side of the equation.
22 + 4X + -22 + 6x = 40 + -22

Reorder the terms:
22 + -22 + 4X + 6x = 40 + -22

Combine like terms: 22 + -22 = 0
0 + 4X + 6x = 40 + -22
4X + 6x = 40 + -22

Combine like terms: 40 + -22 = 18
4X + 6x = 18

Add '-6x' to each side of the equation.
4X + 6x + -6x = 18 + -6x

Combine like terms: 6x + -6x = 0
4X + 0 = 18 + -6x
4X = 18 + -6x

Divide each side by '4'.
X = 4.5 + -1.5x

Simplifying
X = 4.5 + -1.5x

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