3(2x+3x)=2(3x+4x)+1

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Solution for 3(2x+3x)=2(3x+4x)+1 equation: 



3(2x+3x)=2(3x+4x)+1

We move all terms to the left:

3(2x+3x)-(2(3x+4x)+1)=0

We add all the numbers together, and all the variables

3(+5x)-(2(+7x)+1)=0

We multiply parentheses

15x-(2(+7x)+1)=0



We calculate terms in parentheses: -(2(+7x)+1), so:

2(+7x)+1

We multiply parentheses

14x+1

Back to the equation:

-(14x+1)



We get rid of parentheses

15x-14x-1=0

We add all the numbers together, and all the variables

x-1=0

We move all terms containing x to the left, all other terms to the right

x=1

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