3(2x+3)=7(x+2)=0

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Solution for 3(2x+3)=7(x+2)=0 equation: 



3(2x+3)=7(x+2)=0

We move all terms to the left:

3(2x+3)-(7(x+2))=0

We multiply parentheses

6x-(7(x+2))+9=0



We calculate terms in parentheses: -(7(x+2)), so:

7(x+2)

We multiply parentheses

7x+14

Back to the equation:

-(7x+14)



We get rid of parentheses

6x-7x-14+9=0

We add all the numbers together, and all the variables

-1x-5=0

We move all terms containing x to the left, all other terms to the right

-x=5

x=5/-1

x=-5

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