3(2x+3)=6(7x+2)+8

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Solution for 3(2x+3)=6(7x+2)+8 equation: 



3(2x+3)=6(7x+2)+8

We move all terms to the left:

3(2x+3)-(6(7x+2)+8)=0

We multiply parentheses

6x-(6(7x+2)+8)+9=0



We calculate terms in parentheses: -(6(7x+2)+8), so:

6(7x+2)+8

We multiply parentheses

42x+12+8

We add all the numbers together, and all the variables

42x+20

Back to the equation:

-(42x+20)



We get rid of parentheses

6x-42x-20+9=0

We add all the numbers together, and all the variables

-36x-11=0

We move all terms containing x to the left, all other terms to the right

-36x=11

x=11/-36

x=-11/36

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