3(2x+3)-8=4+3(1+x)

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Solution for 3(2x+3)-8=4+3(1+x) equation: 



3(2x+3)-8=4+3(1+x)

We move all terms to the left:

3(2x+3)-8-(4+3(1+x))=0

We add all the numbers together, and all the variables

3(2x+3)-(4+3(x+1))-8=0

We multiply parentheses

6x-(4+3(x+1))+9-8=0



We calculate terms in parentheses: -(4+3(x+1)), so:

4+3(x+1)

determiningTheFunctionDomain
3(x+1)+4

We multiply parentheses

3x+3+4

We add all the numbers together, and all the variables

3x+7

Back to the equation:

-(3x+7)



We add all the numbers together, and all the variables

6x-(3x+7)+1=0

We get rid of parentheses

6x-3x-7+1=0

We add all the numbers together, and all the variables

3x-6=0

We move all terms containing x to the left, all other terms to the right

3x=6

x=6/3

x=2

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