3(2x+3)-2(3x+2)=3(x+2)+2

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Solution for 3(2x+3)-2(3x+2)=3(x+2)+2 equation: 



3(2x+3)-2(3x+2)=3(x+2)+2

We move all terms to the left:

3(2x+3)-2(3x+2)-(3(x+2)+2)=0

We multiply parentheses

6x-6x-(3(x+2)+2)+9-4=0



We calculate terms in parentheses: -(3(x+2)+2), so:

3(x+2)+2

We multiply parentheses

3x+6+2

We add all the numbers together, and all the variables

3x+8

Back to the equation:

-(3x+8)



We add all the numbers together, and all the variables

-(3x+8)+5=0

We get rid of parentheses

-3x-8+5=0

We add all the numbers together, and all the variables

-3x-3=0

We move all terms containing x to the left, all other terms to the right

-3x=3

x=3/-3

x=-1

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