3(2x+3)+11=2(x+3)+18

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Solution for 3(2x+3)+11=2(x+3)+18 equation: 



3(2x+3)+11=2(x+3)+18

We move all terms to the left:

3(2x+3)+11-(2(x+3)+18)=0

We multiply parentheses

6x-(2(x+3)+18)+9+11=0



We calculate terms in parentheses: -(2(x+3)+18), so:

2(x+3)+18

We multiply parentheses

2x+6+18

We add all the numbers together, and all the variables

2x+24

Back to the equation:

-(2x+24)



We add all the numbers together, and all the variables

6x-(2x+24)+20=0

We get rid of parentheses

6x-2x-24+20=0

We add all the numbers together, and all the variables

4x-4=0

We move all terms containing x to the left, all other terms to the right

4x=4

x=4/4

x=1

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