3(2x+3)+11=-(2x-6)-18

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Solution for 3(2x+3)+11=-(2x-6)-18 equation: 



3(2x+3)+11=-(2x-6)-18

We move all terms to the left:

3(2x+3)+11-(-(2x-6)-18)=0

We multiply parentheses

6x-(-(2x-6)-18)+9+11=0



We calculate terms in parentheses: -(-(2x-6)-18), so:

-(2x-6)-18

We get rid of parentheses

-2x+6-18

We add all the numbers together, and all the variables

-2x-12

Back to the equation:

-(-2x-12)



We add all the numbers together, and all the variables

6x-(-2x-12)+20=0

We get rid of parentheses

6x+2x+12+20=0

We add all the numbers together, and all the variables

8x+32=0

We move all terms containing x to the left, all other terms to the right

8x=-32

x=-32/8

x=-4

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