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3(2x+3)(x-7)=0
We multiply parentheses ..
3(+2x^2-14x+3x-21)=0
We multiply parentheses
6x^2-42x+9x-63=0
We add all the numbers together, and all the variables
6x^2-33x-63=0
a = 6; b = -33; c = -63;
Δ = b2-4ac
Δ = -332-4·6·(-63)
Δ = 2601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2601}=51$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-51}{2*6}=\frac{-18}{12} =-1+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+51}{2*6}=\frac{84}{12} =7 $
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