3(2x+20)=8x+12

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Solution for 3(2x+20)=8x+12 equation: 



3(2x+20)=8x+12

We move all terms to the left:

3(2x+20)-(8x+12)=0

We multiply parentheses

6x-(8x+12)+60=0

We get rid of parentheses

6x-8x-12+60=0

We add all the numbers together, and all the variables

-2x+48=0

We move all terms containing x to the left, all other terms to the right

-2x=-48

x=-48/-2

x=+24

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