3(2x+2)=4(3x+2)-4(x+3)

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Solution for 3(2x+2)=4(3x+2)-4(x+3) equation: 



3(2x+2)=4(3x+2)-4(x+3)

We move all terms to the left:

3(2x+2)-(4(3x+2)-4(x+3))=0

We multiply parentheses

6x-(4(3x+2)-4(x+3))+6=0



We calculate terms in parentheses: -(4(3x+2)-4(x+3)), so:

4(3x+2)-4(x+3)

We multiply parentheses

12x-4x+8-12

We add all the numbers together, and all the variables

8x-4

Back to the equation:

-(8x-4)



We get rid of parentheses

6x-8x+4+6=0

We add all the numbers together, and all the variables

-2x+10=0

We move all terms containing x to the left, all other terms to the right

-2x=-10

x=-10/-2

x=+5

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