3(2x+2)=3(x+1)+3x+3

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Solution for 3(2x+2)=3(x+1)+3x+3 equation: 



3(2x+2)=3(x+1)+3x+3

We move all terms to the left:

3(2x+2)-(3(x+1)+3x+3)=0

We multiply parentheses

6x-(3(x+1)+3x+3)+6=0



We calculate terms in parentheses: -(3(x+1)+3x+3), so:

3(x+1)+3x+3

We add all the numbers together, and all the variables

3x+3(x+1)+3

We multiply parentheses

3x+3x+3+3

We add all the numbers together, and all the variables

6x+6

Back to the equation:

-(6x+6)



We get rid of parentheses

6x-6x-6+6=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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