3(2x+2)=3(x+1)

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Solution for 3(2x+2)=3(x+1) equation: 



3(2x+2)=3(x+1)

We move all terms to the left:

3(2x+2)-(3(x+1))=0

We multiply parentheses

6x-(3(x+1))+6=0



We calculate terms in parentheses: -(3(x+1)), so:

3(x+1)

We multiply parentheses

3x+3

Back to the equation:

-(3x+3)



We get rid of parentheses

6x-3x-3+6=0

We add all the numbers together, and all the variables

3x+3=0

We move all terms containing x to the left, all other terms to the right

3x=-3

x=-3/3

x=-1

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