3(2x+2)=17-2(x-1)

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Solution for 3(2x+2)=17-2(x-1) equation:



3(2x+2)=17-2(x-1)
We move all terms to the left:
3(2x+2)-(17-2(x-1))=0
We multiply parentheses
6x-(17-2(x-1))+6=0
We calculate terms in parentheses: -(17-2(x-1)), so:
17-2(x-1)
determiningTheFunctionDomain -2(x-1)+17
We multiply parentheses
-2x+2+17
We add all the numbers together, and all the variables
-2x+19
Back to the equation:
-(-2x+19)
We get rid of parentheses
6x+2x-19+6=0
We add all the numbers together, and all the variables
8x-13=0
We move all terms containing x to the left, all other terms to the right
8x=13
x=13/8
x=1+5/8

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