3(2x+2)-3x=6(-3x-4)

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Solution for 3(2x+2)-3x=6(-3x-4) equation: 



3(2x+2)-3x=6(-3x-4)

We move all terms to the left:

3(2x+2)-3x-(6(-3x-4))=0

We add all the numbers together, and all the variables

-3x+3(2x+2)-(6(-3x-4))=0

We multiply parentheses

-3x+6x-(6(-3x-4))+6=0



We calculate terms in parentheses: -(6(-3x-4)), so:

6(-3x-4)

We multiply parentheses

-18x-24

Back to the equation:

-(-18x-24)



We add all the numbers together, and all the variables

3x-(-18x-24)+6=0

We get rid of parentheses

3x+18x+24+6=0

We add all the numbers together, and all the variables

21x+30=0

We move all terms containing x to the left, all other terms to the right

21x=-30

x=-30/21

x=-1+3/7

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