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3(2x+11)=5(x-4)
We move all terms to the left:
3(2x+11)-(5(x-4))=0
We multiply parentheses
6x-(5(x-4))+33=0
We calculate terms in parentheses: -(5(x-4)), so:We get rid of parentheses
5(x-4)
We multiply parentheses
5x-20
Back to the equation:
-(5x-20)
6x-5x+20+33=0
We add all the numbers together, and all the variables
x+53=0
We move all terms containing x to the left, all other terms to the right
x=-53
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