3(2x+10)=-8(x-2)

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Solution for 3(2x+10)=-8(x-2) equation: 



3(2x+10)=-8(x-2)

We move all terms to the left:

3(2x+10)-(-8(x-2))=0

We multiply parentheses

6x-(-8(x-2))+30=0



We calculate terms in parentheses: -(-8(x-2)), so:

-8(x-2)

We multiply parentheses

-8x+16

Back to the equation:

-(-8x+16)



We get rid of parentheses

6x+8x-16+30=0

We add all the numbers together, and all the variables

14x+14=0

We move all terms containing x to the left, all other terms to the right

14x=-14

x=-14/14

x=-1

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