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3(2x+1)=6(x+5)
We move all terms to the left:
3(2x+1)-(6(x+5))=0
We multiply parentheses
6x-(6(x+5))+3=0
We calculate terms in parentheses: -(6(x+5)), so:We get rid of parentheses
6(x+5)
We multiply parentheses
6x+30
Back to the equation:
-(6x+30)
6x-6x-30+3=0
We add all the numbers together, and all the variables
-27!=0
There is no solution for this equation
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